This no longer uses the fill color. It now uses the stroke color, consistent with the documentation.
PHP - Manual: ImagickDraw::point
2024-11-14
(PECL imagick 2, PECL imagick 3)
ImagickDraw::point — Draws a point
$x
, float $y
): bool本函数还未编写文档,仅有参数列表。
Draws a point using the current stroke color and stroke thickness at the specified coordinates.
x
point's x coordinate
y
point's y coordinate
没有返回值。
示例 #1 ImagickDraw::point() example
<?php
function point($fillColor, $backgroundColor) {
$draw = new \ImagickDraw();
$draw->setFillColor($fillColor);
for ($x = 0; $x < 10000; $x++) {
$draw->point(rand(0, 500), rand(0, 500));
}
$imagick = new \Imagick();
$imagick->newImage(500, 500, $backgroundColor);
$imagick->setImageFormat("png");
$imagick->drawImage($draw);
header("Content-Type: image/png");
echo $imagick->getImageBlob();
}
?>
This no longer uses the fill color. It now uses the stroke color, consistent with the documentation.
point($x, $y) uses the FillColor of ImagickDraw! This actually took quite a while, till I found out that it's falsely documented on these pages. So to draw single pixels, do it like this:
<?php
$image = new Imagick();
$draw = new ImagickDraw();
$pixel = new ImagickPixel('red');
$image->newImage(10, 10, 'transparent', 'gif');
// Here comes the magick:
$pixel->setColor($_POST[$i."x".$j]);
$draw->setFillColor($pixel);
$draw->point($i,$j);
$image->drawImage($draw);
$image->writeImages($path, true);
?>